You have a sample of C4H9Cl. You are not sure what the exact structure of the molecule is. You do two trials of a reaction with this molecule:
Trial 1: .10M C4H9Cl and .10M Br-
Trial 2: .10M C4H9Cl and .20M Br-
you notice that in the second trial, the reaction occurs twice as fast. What mechanism is probably followed (Sn1, Sn2, E1, E2)? Choose a possible starting molecule. Draw mechanism if at all possible.
2007-04-01 14:29:15 · 2 answers · asked by JaJarvis 1 in Science & Mathematics ➔ Chemistry
Well, the data suggests that it's first order in Br-, which means that Br- is involved in the mechanism. I suggest nucleophilic attack by Br- on the C atom containing the Cl atoms. The mechanism will be SN2.
2007-04-01 21:19:13 · answer #1 · answered by Gervald F 7 · 0⤊ 0⤋
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2016-12-03 03:27:05 · answer #2 · answered by ? 4 · 0⤊ 0⤋