A 20 newton block is at rest at the bottom of a frictionless incline.?

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A 20 newton block is at rest at the bottom of a frictionless incline.?

The base of the incline is 4.0m and the height of the incline is 3.0m.

How much work must be done against gravity to move the block to the top of the incline?

a. 10 J
b. 60 J
c. 80 J
d. 100 J

2007-04-01 13:26:16 · 3 answers · asked by Anonymous in Science & Mathematics ➔ Physics

3 answers

B = 60 J

2007-04-01 13:31:09 · answer #1 · answered by Thomas C 6 · 0⤊ 0⤋

the work = 20*3=60 J as 20 N = m*g
The base date is not needed as the work done equals the potential energy gane becaus e the incline is frictionless

2007-04-01 13:35:34 · answer #2 · answered by santmann2002 7 · 0⤊ 0⤋

Conserving energy you get
Work done=mgh=20*3=60
ans = b. 60J

2007-04-01 13:31:58 · answer #3 · answered by Saurabh 1 · 0⤊ 0⤋