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I need help finding the missing angles and sides. If you could show your work that would really help me understand the steps. Thank you very much!

Side a = 30
Side b =
Side c = 78
Angle A = 22.62 degrees
Angle B =
Angle C =

2007-04-01 10:19:20 · 4 answers · asked by Shawn 1 in Science & Mathematics Mathematics

4 answers

your information rerpesents 2 sides and one angle, SSA

The formula for a SSA Triangle is the law of sines

sinC / c = sinA / a

- - - - - - - - - - -

Additional information

SAA = side, angle, angle

Formula

a / sinA = b / sin B

or

b / sinB = c /sinC

- - - - - - - - - - -s-

2007-04-01 11:32:02 · answer #1 · answered by SAMUEL D 7 · 0 0

http://www.analyzemath.com/Triangle/sine_law_0.gif

Refer to this to get an idea of where the sides and angles are.

First use the sine law to calculate the angle at c
Then, using that angle, calculate angle B (since angle(A+B+C)=180 (Sum of the interior angles in a trianlge)

Then use the cosine law to calculate the length of side b

b^2=a^2+c^2-2(a)(c)(cosB)

Then you're done…

I can't actually do it because there seem to be something wrong with your data. Please check it,

2007-04-01 17:35:54 · answer #2 · answered by Carp Face 4 · 0 0

two sides and one angle are given, use sine law

a/SinA = c/sinC

30/sin(22.62) = 78/sinC

78sin(22.62) = 30sinC

sinC = 1.000005657

C = sin^-1 ( 1.000005657)

the triangle can not be solved

2007-04-01 17:25:26 · answer #3 · answered by      7 · 0 1

look up the law of cosines and use that.

2007-04-01 17:26:23 · answer #4 · answered by bignose68 4 · 0 1

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