1.5a^2-14a-3=0
(5a+1)(a-3)=0
5a+1=0
a-3=0
a=-1/5 or 3
2.x(2x-3)=x^2+10
2x^2-3x=x^2+10
x^2-3x-10=0
(x+2)(x-5)=0
x+2=0
x-5=0
x=-2 or 5
I hope this helps and good luck with your class!
2007-04-01 09:54:22
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answer #1
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answered by Anonymous
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1. 5a^2-14a-3=0
(5a+1)(a-3) =0
5a+1=0 a-3=0
a= -1/5 a=3
2. 2x^2 - 3x = x^2 +10
x^2 - 3x - 10 = 0
(x-5)(x+2)=0
x=5 or x= -2
2007-04-01 16:54:59
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answer #2
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answered by Anonymous
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On number one, you first must factor into (5a + 1)(a - 3). You then need to set both sets of parenthesis equal to zero.
5a + 1 = 0 and a - 3 = 0. In 5a + 1 = 0, subtract one from both sides leaving you with 5a = -1. You then divide both sides by 5 which leaves you with a = -1/5. In a - 3 = 0, you simply add 3 to both sides, leaving you with a = 3.
On number two, you first must distribute the x through the parenthesis, giving you 2x^2 - 3x = x^2 + 10. Subtract x^2 from both sides leaving you with x^2 - 3x = 10. Then subtract 10 from both sides leaving you with x^2 - 3x - 10. From there, factor into (x - 5) (x + 2). Set both equal to zero and solve. Final answer x = 5, x = -2.
2007-04-01 17:04:03
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answer #3
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answered by htimsnahgem 1
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5a² - 14a - 3 = 0
the middle term is - 14a
Find the sum of the middle term
Multiply the first term 5 times the last term 3 equals 15 and factor
factors of 15
1 x 15. . .<= use these factors
3 x 5
1 abd - 15 satisry the sum of the middle term
1 = a
insert + a - 15a into the equation
5x² - 14a - 3
5a² + a - 15a - 3
a(5x + 1) - 3(5a + 1)
(a - 3)(5a + 1)
- - - - - - - - - - s-
2007-04-01 17:16:54
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answer #4
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answered by SAMUEL D 7
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1. factor it:
(5a + 1)(1a - 3)= 0
a= -1/5 and a =3
2. 2x^2 -3x = x^2 + 10
x^2 -3x -10= 0
(x -5)(x+2) = 0
x=5 and x = -2
2007-04-01 16:56:13
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answer #5
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answered by bignose68 4
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1) 5a^2-14a-3=0
(5a +1)(a-3)
a = -.2 or 3
2) x(2x-3) = x^2+10
2x^2 - 3x = x^2 + 10
x^2 - 3x - 10 = 0
(x-5)(x+2) = 0
x = 5 or -2
2007-04-01 16:52:50
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answer #6
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answered by Steve A 7
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Factor the first one to get:
(5a+1)(a-3)
a=-1/5 a=3
2. Distribute the x
2x^2-3x=x^2+10
Simplify and move terms to one side
x^2-3x-10=0
(x-5)(x+2)
x=5 x=-2
2007-04-01 16:52:42
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answer #7
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answered by llllarry1 5
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1) a= 1/5 or a=3
2) x=5 or x=-2
2007-04-01 16:59:07
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answer #8
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answered by Dm 2
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