Math Help!!?

Question

does anyone know the answer to : if 0 < x < 1 and 0 < y < 1, which of the following must be true... a) xy >0 ... b) xy<0 ... c) x/y <0 ....d) x-y >0 ... e) x-y <0 and can some1 tell me the answer to the q. "the tens digit of a 2-digit number is 3 and the units digit is "h". If the 2-digit number id divisible by "h", which CANNOT be the value of "h"? a) 2 ... b) 3... c) 4... d)5... and e) 6...... i'd really appreciate the anwers cuz i can't figure it out!

Answer 1

You can do it.
First problem:
Choose some sample values for x and y, such as x=1/2 and y=1/2. Then see whether a, b, c, d, and e are true. If only one is true, you're done. If not, note which ones are true, and try another combination of x and y to see whether only one of those remaining possibilities is true.

Second problem:
Just try every number that starts with 3 and ends with one of those digits, and see whether it's divisible by that digit:
Is 32 divisible by 2?
Is 33 divisible by 3?
etc.

It's not hard.
GO TO IT!!!

Answer 2

The answer to the first question must be "a." Since neither x nor y are less than 0, their product cannot be less than 0, nor can their quotient. Also, since their relative values are not known, we cannot say that "d" and "e" are true.

Although some answerers are using a trial method for this second question, there is a slightly different way to figure this out.

If we call the given number x, then x = 30 + h.

If x is divisible by h, then x = hk.

Now we can equate the two numbers to get this:

30 + h = hk
(30 + h) / h = k
30 / h + 1 = k

Now we make these observations. If h divides 30 + h evenly, then k must be an integer. Since k = 30 / h + 1 is an integer, then 30 / h must also be an integer. The only way for this to be true is for h to divide 30 evenly. So, we need only look to see whether the list of our numbers are divisors of 30. If they are, they will work. If not, they must be rejected. Looking through our list, only 4 does not divide 30, so it is the only one which doesn't work. So "c" must the answer to the last question.

Answer 3

ANS 1) let x be 0.5. Let y be 0.25. Therefore, x * y > 0.
{(0 + x) (0 + y) = xy which > 0.}

ANS 2)The number is in the form of 3 * 10 + h (as 3 is the tens digit.) = 30 + h. Here, the value of h can be only 4 (as 34 is not divisible by 4.

Answer 4

on thie first one a the only one that's always true because we're dealing with 2 positive numbers and the product/quotient can never be negative but since you don't know what the two numbers are you can't tell what the sign of the difference is

on the second question the answer is c:

32/2=16
33/3=11
34/4=17/2 (not a whole number)
35/5=7
36/6=6

have a nice day!