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An economics professor randomly selected 100 millionaires in the U.S. The average age of these millionaires was 52.1 years with a standard deviation of 12.3 years. What is a 99.5% confidence interval for the mean age, m, of all U.S. millionaires?



a. 48.6 < m < 55.6

b. 48.9 < m < 55.3

c. 49.2 < m < 55.0

d. 49.7 < m < 54.5

e. 50.1 < m < 54.1

f. none of these

2007-04-01 05:38:00 · 2 answers · asked by chris 2 in Science & Mathematics Mathematics

2 answers

[52.1 - 2.575*12.3/sqrt(100) , 52.1 + 2.575*12.3/sqrt(100)]

= [48.93275, 55.26725]

= [48.9, 55.3] (b.)

2007-04-01 05:44:14 · answer #1 · answered by Anonymous · 0 0

use t test and then go on with your life.

2007-04-01 12:50:48 · answer #2 · answered by gjmb1960 7 · 0 1

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