2007-04-01 04:59:59 · 6 answers · asked by ree_na00 1 in Science & Mathematics ➔ Mathematics
4x^2 + 14x - 60
= 2(2x^2 + 7x - 30)
= 2(x + 6)(2x - 5)
2007-04-01 05:02:38 · answer #1 · answered by Anonymous · 0⤊ 1⤋
4x^2 + 14x - 60 can be written as 2(2x^2 + 7x - 30) and that can be further factored as:
(x + 6) and (2x - 5) and so the factors are:
2 (x + 6) (2x - 5)
2007-04-01 12:06:03 · answer #2 · answered by Swamy 7 · 0⤊ 0⤋
4x²+14x-60
= 2 (2x²+7x-30)
=2(2x-5)(x+6)
2007-04-01 12:09:49 · answer #3 · answered by yuk 2 · 0⤊ 0⤋
4x^2 + 14x - 60
= 2(2x^2 + 7x - 30)
= 2(x + 6)(2x - 5)
therefore either (x+6) = 0
or (2x - 5) = 0
if x+6 = 0
x = -6
if 2x -5 = 0
2x = 5
x = 5/2
x = 3.5
so x = 3.5 or -6!
2007-04-01 12:25:18 · answer #4 · answered by noahukusa 2 · 0⤊ 0⤋
2(2x-5)(x+6)
2007-04-01 12:14:32 · answer #5 · answered by Kathleen K 7 · 0⤊ 0⤋
(2x+12)(2x - 5)
2007-04-01 12:08:20 · answer #6 · answered by Colin 6 · 0⤊ 0⤋