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Ag2CrO4(s)-->reversible reaction<----2Ag^1+ + CrO4^2-

2007-04-01 03:33:25 · 4 answers · asked by mike 1 in Science & Mathematics Chemistry

the products are both (aq) solutions

2007-04-01 03:35:16 · update #1

4 answers

K = [Ag+]^2[CrO4(2-)]

Solids and liquids do not appear in the equilibrium expression. Only gases and species in solution.

2007-04-01 03:43:16 · answer #1 · answered by TheOnlyBeldin 7 · 0 0

the solid Ag2CrO4 should not be taken into account in the eqm. expression and thus the expression only takes into account the concentrations of only the substances in aq. states

thus it is = [Ag+]^2[CrO4 2-]

2007-04-01 10:55:29 · answer #2 · answered by llcold 2 · 0 0

This is a Ksp expression.

Ksp = [Ag+]^2 * [CrO4--]

The activity of solids is, by convention, 1, so no need to put solid silver chromate in the denominator.

2007-04-01 11:37:55 · answer #3 · answered by Robert J 2 · 0 0

( [AG]^2 x [CrO4] )

Never include solids
Always include gases and aqueous
Never include liquids UNLESS every compound in the reaction is liquid (meaing homogenous)
If lets say both the products are liquid and the reactant is aqueous, you would not include the products since it's a heterogeneous mixture.

2007-04-01 11:06:30 · answer #4 · answered by Kipper to the CUP! 6 · 0 0

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