Use tan(60) = opposite/adjacent = 32/x
3^1/2 = 32/x
3^1/2 * x = 32
x = 32/(3^1/2)
Now rationalize your denominator, and you're done!
good luck!
BTW -- see below -- the shorter leg is NOT the one opposite the 60° angle.
Awwww -- never mind -- he edited his mistake. . .
2007-03-31 17:44:54
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answer #1
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answered by birdwoman1 4
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For a 60° angle in a right triangle the relation of the sides is:
adjacent:hypotenuse:opposite = 1:2:â3
the ratio of the side adjacent to the side opposite, then, is 1/â3, so
1/â3 = x/32
x = 32/â3
Getting rid of the radical in the denominator,
x = 32â3/(â3â3) = (32â3)/3
2007-04-01 00:57:17
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answer #2
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answered by Helmut 7
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did you learn your 30-60-90 triangles yet? if it's right triangle, then one angle is 60, another must be 90, so (180-60-90=30) 30 is other side. If side across from 30 is x, then side across from 60 is (root 3)x and side across from 90 is 2x. So 32 divided by root 3 equals (32/(root 3)). to simplify multiply by (root 3)/(root 3) you get 32(root 3)/ 3.
If you don't get the 30-60-90 thing, just prove w/ pyth thm. 1 squared (which is 1) plus root 3 squared (which is 3) equals 4 (which is 2 squared.
Hope that answers your ?. BTW, why are you doin math on sat. night?
2007-04-01 00:47:39
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answer #3
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answered by The Ghetto David Hume 3
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In 30-60-90 degree triangle, the longer leg is always â3 times the shorter leg.
32 = â3 x
x = 32/â3 = 32â3/3
2007-04-01 00:45:51
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answer #4
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answered by sahsjing 7
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First note:
In a right triangle the tangent of an angle tan(a) = the opposite side/ajacent side
In this problem you can set it up such that: tan(60)=x/32
Now you simply solve for x. tan(60) = â3.
x = 32/â3 = 32â3/3
2007-04-01 00:47:58
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answer #5
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answered by lukedu186 2
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Because this is a right triangle,
tan 60 degrees = tan (pi/3) = 32/x ie the side opposite/side adjacent
x = 32/tan (pi/3) = 32/[sqr(3)] = 32sqr[3]/3
Remember that tan (pi/3) = sqr[3], good to commit this to memory
2007-04-01 00:51:43
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answer #6
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answered by kellenraid 6
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Yeah the answer is 18.48. Because tan(x)=opposite/adjacent.. and if you take x to be 60 and plug the rest of the stuff in, it comes out that way
2007-04-01 01:45:32
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answer #7
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answered by Anonymous
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tan(A) = opposite/adjacent
tan(60) = 32/x
x = 32/(tan(60))
x = 32/(sqrt(3))
to get rid of the sqrt value, multiply top and bottom by sqrt(3)
x = (32sqrt(3))/3
2007-04-01 01:00:19
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answer #8
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answered by Sherman81 6
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