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The diagonal is 13 and the length is 12. You need to find the width and the three sides make a right triangle. For a right triangle, the sides are a^2 + b^2 = c^2. (The diagonal is the c^2). So ...

a^2 + b^2 = c^2
a^2 + 12^2 = 13^2
a^2 = 13^2 - 12^2
a = sqrt(13^2 - 12^2)
a = 5 = width

2007-03-31 08:29:45 · answer #1 · answered by RyanGoff 2 · 0 0

c² = a² + b²

c² - a² = b² . . .Use this formula

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± √(13²) - (12)² = √b²

± √169 - 144 = √b²

± √25 = √b²

± 5 = b

The width is ± 5 inches

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2007-03-31 16:13:29 · answer #2 · answered by SAMUEL D 7 · 0 0

the diagnal is the hypotenue.

a^2 + b^2 = c^2
12^2 + b^2 = 13^2
c^2 = 25
c = 5

the width is 5

2007-03-31 15:29:31 · answer #3 · answered by      7 · 0 0

width = sqrt.(daigonal^2 - length^2)
=sqrt.(169-144)
=sqrt25
=5 in

2007-03-31 15:55:41 · answer #4 · answered by sushobhan 6 · 0 0

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