how do u calculate the distance travelled by a projectile?

Answer 1

You will need to calculate the total time it is in the air. Then use the angle at which it was projected to calculate the horizontal velocity. Once you have the time and the velocity you can use d = vt to calculate the distance.

Answer 2

Using two formulae you can do this task
1) S = ut + 1/2 a t^2
2) V = u + at

S is the total distance, u initial velocity, v final velocity, t time and a acceleration.

to calculate S you need to know some of the other parameters in these equations. Use any one which has all other data except one and after finding that put these into the other equation to get S. Its possible that you have enough information to use equation 1 straight away.

Answer 3

I think distance equals speed multiplied by time.
d=st
So if you know how fast that projectile was going and the time it stayed moving. I guess you could calculate it from that.

Answer 4

If the question is:
How many feet away from you did the ball land?

x = [v(0)^2 sin(2th) ] / g
where v(0) is the initial velocity, "th" is the angle it was launched, and g is 9.8 m/sec^2
This is called "horizontal range"


If you want to know the length of the trajectory:

The trajectory has the equation "y" in terms of "x":

y = x tan(th) - [ (g/2)* (x / v(0)*cos(th) )^2 ) ]

where, again v(0) is the initial velocity, "th" is the angle it was launched and g is 9.8 m/sec^2

Find the length of the parabolic curve
from x = 0 to x = [v(0)^2 sin(2th) ] / g

s = Integral {0 to [v(0)^2 sin(2th) ] / g } of { sqrt [1 +( y')^2 ] dx}

y' = tan(th) - [ (g*x) / (v(0)*cos(th))^2 ) ]

Take it from there...

Answer 5

http://en.wikipedia.org/wiki/Trajectory_of_a_projectile