is my answer to this question correct ?

Question

Question: Cystic fibrosis is an autosomal recessive trait in human beings. Denote the mutant allele bye c and the normal by C. What percent are expected genotypes, genotypic ratios, phenotypes and phenotypic ratios if both parents are heterozygotes.


Answer: If both parents are heterozygotes, 3 out of 4 of the offspring (children) will be normal phenotype, meaning that they will not inherit cystic fibrosis. This also means that there is a 1 out of 4 chance that the couple will have a child with the disease. In other words, there is a 75% chance that the parents will have a 75% of having normal children and a 25% chance of having children that will have cystic fibrosis. The genotypic ratio is is 1:2:1, meaning that there is one offspring that is homozygous dominant CC and one that is homozygous recessive, cc, and 2 that are heterozygous carriers: Cc, like their parents.

Answer 1

50:50
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Answer 2

No, you have not quite correctly, but you have gone in the right direction. The chances of being a carrier, normal or abnormal exist for each child that is born. It is not correct to say that 25% of children will be normal.
You should answer something like this: For each of the offspring of two carriers (Cc) there is a 25% chance of being affected by CF (cc genotype), a 50% chance of being a carrier (Cc) and 25% chance of being normal (CC). This is for each child. they could have all affected children, or all carriers or all normal.
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Answer 3

u are right to the maximum extent but at one place u got stumped in ur answer u wrote they THEY WILL NOT INHERIT thos is wrong..........sorry to tell
cc--------disease[25%]homozygous ressisive

Cc-----------carier[50%]heterozygous
CC----------normal[25%]homozygous dominat
the further generation willll be saved of that disease if other partner is purely homozygous dominant ........
gracoius

Answer 4

yeah