2007-03-30 15:43:57 · 12 answers · asked by sexylatina0321 1 in Science & Mathematics ➔ Mathematics
Subtract 8x from both sides:
4x=40
Divide 4 from both sides:
x=10
Check:
8(10)+40=12(10)
80+40=120
120=120
2007-03-30 15:46:59 · answer #1 · answered by Anonymous · 4⤊ 0⤋
First you need to combine like terms. So, you will subtract 8x from 12x. Then you'll get this:
40=4x
Then, you need to get the 'x' by itself. So, you will divide 40 and 4 by 4. Like this:
40/4=4x/4
Dividing the 4x by the 4 cancels out the 4, leaving just the x. Then you divide 40 by 4, which gets you 10.
x=10
2007-03-30 22:52:54 · answer #2 · answered by Anonymous · 1⤊ 0⤋
8x + 40 = 12x
Subtract 8x from each side:
40 = 4x
Divide by 4:
10 = x
2007-03-30 23:10:42 · answer #3 · answered by tweedfalcon 2 · 1⤊ 0⤋
8x + 40 = 12x
(you want to put all the x on the same side so...)
40 = 12x - 8 x
40 = 4x
(given that you wan to solve for x...)
40/4 = 4x/4
10 = x
2007-03-30 22:48:06 · answer #4 · answered by Sarah Morgan-White 2 · 3⤊ 0⤋
8x + 40 = 12x
Subtract 8x from both sides.
40 = 4x
Divide both sides by 4
x = 10
2007-03-30 22:47:23 · answer #5 · answered by rebkos 3 · 4⤊ 0⤋
8X+40=12X
8x - 12x = -40
-4x = -40
x = -40/-4
x = 10
Solution: {x belongs to R| x = 10}
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2007-03-30 23:54:27 · answer #6 · answered by aeiou 7 · 1⤊ 0⤋
8x+40=12x
40=12x-8x
40=4x
x=40/4
x=4 divided by 40which is equal to 10
Ans=10
2007-03-30 23:49:30 · answer #7 · answered by spicygirl_atparadise 1 · 1⤊ 0⤋
40 = 4x
x = 10
2007-03-31 04:35:06 · answer #8 · answered by Como 7 · 0⤊ 0⤋
8X+40=12X
8X-8X(canceled out)40=12X-8X
40=4X
40/4=4X/4
10=x
x=10
Then sub. 10 for "X"
8X+40=12X
8(10)+40=12(10)
80+40=120
120=120
Hope it helps!
2007-03-30 23:30:55 · answer #9 · answered by sweet 2 · 1⤊ 0⤋
8X+40=12X
12X-8X = 40
4x = 40
x = 10
2007-03-30 23:22:15 · answer #10 · answered by josh.weissbock 3 · 1⤊ 0⤋