What is the limit of arcsin(x) when x approaches infinity?

Question

As well, what is the limit when x approaches negative infinity?

There is a mistake in the question, as has been pointed out.. I think what I meant to ask was, instead of (arcsin x) was (1/sinx)

Answer 1

arcsin(x) means what angle has a sin value = x

e.g. arcsin(0) = 0
e.g. arcsin(1) = 90 degrees
e.g. arcsin(-1) = -90 degrees.

x in this case can only be a value from -1 to +1

e.g. arcsin(2) is undefined.

therefore your question has a problem in asking for x to approach infinity.

Answer 2

The range of x is -1 =< x =< 1. y is the parameter that varies fro - infinity to + infinity.

Answer 3

simply graph it and see what value on the y axis the funtion approaches as you move along the x axis to the right

if the line gradually moves up as you move along the answer can be infinti or vica versa