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1: Factor.
3x2 - 192

(x - 8)(x + 8)
3(x+ 8)(x + 8)
3(x - 8)(x + 8)


2: 162x2 - 8
2(9x - 2)(9x + 2)
2(9x - 2)(9x - 2)
(9x - 2)(9x + 2)


3: 2x2 - 28x + 48
2(x - 4)(x - 6)
2(x - 2)(x - 12)
(x - 2)(x - 12)


4: 3x2 - 30x + 63
(x - 21)(x - 3)
3(x + 7)(x - 3)
3(x - 7)(x - 3)


5: 16x2 - 8x + 1
(4x - 1)(4x - 1)
(8x - 1)(2x - 1)
(16x - 1)(x - 1)


6: 3x2 - 42x + 72
(3x - 12)(x - 2)
3(x - 12)(x - 2)
(x - 12)(x - 2)


7: 4x2 + 8x - 320
(4x - 8)(x + 10)
4(x - 8)(x + 10)
4(x - 16)(x + 5)


8: 2x2 + 10x + 12
2(x + 2)(x + 3)
(x + 3)(2x - 4)
(2x + 3)(x + 4)


9: 9x2 - 3x + 18x - 6
(x + 2)(3x - 1)
(3x + 2)(3x - 1)
3(x + 2)(3x - 1)


10: 2x3 - 2x + 3x2 - 3
(x - 1)(2x - 3)
2(x + 1)(x - 1)(x + 3)
(x + 1)(x - 1)(2x + 3)


11: 3x3 + 3x2 - 27x - 27
3(x - 9)(x - 3)
3(x + 1)(x + 3)(x - 3)
(x + 1)(x + 3)(x - 3)


12: (x4 - 16)
(X - 2)(X + 2)(X2 + 4)
(X - 2)(X + 2)(X + 4)
(X - 2)(X + 2)(X2 + 2)


13: (Y4 - 81)
(Y - 3)(Y + 3)(Y2 + 9)
(Y - 3)(Y + 3)(Y + 9)
(Y - 3)(Y + 3)(Y2 + 3)


14: 8x2 - 18
(2x + 3)(2x - 3)
2(2x + 3)(2x - 3)
2(2x + 3)(x - 3)


15: 2x2 - 16x + 32
(x - 4)(x - 4)
(2x - 4)(x - 4)
2(x - 4)(x - 4)

2007-03-30 13:10:16 · 6 answers · asked by *MaRiSsA* 2 in Science & Mathematics Mathematics

6 answers

3(x - 8)(x + 8)
2(9x - 2)(9x + 2)
2(x - 2)(x - 12)
3(x - 7)(x - 3)
(4x - 1)(4x - 1)
3(x - 12)(x - 2)
4(x - 8)(x + 10)
2(x + 2)(x + 3)
3(x + 2)(3x - 1)
2(x + 1)(x - 1)(x + 3)
3(x + 1)(x + 3)(x - 3)
(X - 2)(X + 2)(X2 + 4)
(Y - 3)(Y + 3)(Y2 + 9)
2(2x + 3)(2x - 3)
2(x - 4)(x - 4)

2007-03-30 13:37:44 · answer #1 · answered by ironduke8159 7 · 0 0

One question at a time for the purpose of learning technique.

2007-03-30 13:20:21 · answer #2 · answered by dwinbaycity 5 · 1 0

You need an explanation, not an answer. And I don't care to explain that many at once.

2007-03-30 13:25:19 · answer #3 · answered by tedfischer17 3 · 1 0

Why can't you do these yourself? They're all pretty easy, but if you don't know how to figure it out, do a quick guess and check.

2007-03-30 13:16:40 · answer #4 · answered by Vegan 7 · 1 0

Hey, I saw your other question is EXACTLY the same! If you want people to help you...DON'T LIE! I would have helped you but you lied =.= sorry

2007-03-30 13:17:14 · answer #5 · answered by ☆★-§CodersUniverse§-★☆ 2 · 1 0

do your homework

2007-03-30 13:14:56 · answer #6 · answered by itsSCIENCE 2 · 2 1

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