2007-03-30 11:25:19 · 9 answers · asked by Abena 2 in Science & Mathematics ➔ Mathematics
(x-3)(x+5)
2007-03-30 11:35:15 · answer #1 · answered by MAX 1 · 2⤊ 0⤋
An easy way to do this is that you need to get c. That is negative fifteen. The only question you have to ansever is that what can I multiply to get negative fifteen and add those two numbers and get two. You write in factor form. (x+5)(x-3).
2007-03-30 11:34:50 · answer #2 · answered by Anonymous · 1⤊ 1⤋
(x + 5)(x - 3)
2007-03-30 11:29:05 · answer #3 · answered by ajfmf90 2 · 5⤊ 0⤋
x² +2x-15
is a quadratic expression. that is, if you solve the
x, the answers will be,
x = 3 or x = -5
by using the formula:
ax² + bx + c = 0
x= [-b±√(b²-4ac)]/2a
2007-03-30 11:38:27 · answer #4 · answered by edison c d 4 · 0⤊ 0⤋
look for two numbers that multiply to -15 and add to 2
5 and -3
(x+5)(x-3)
2007-03-30 11:31:11 · answer #5 · answered by 7 · 2⤊ 0⤋
(x+5)(x-3)
2007-03-30 11:31:09 · answer #6 · answered by ironduke8159 7 · 2⤊ 0⤋
(x+5)(x-3)
x^2+5x-3x-15
x^2+2x-15
2007-03-30 11:45:47 · answer #7 · answered by Dave aka Spider Monkey 7 · 1⤊ 0⤋
x^2+2x-15
x^2+5x-3x-15
x(x+5)-3(x+5)
(x-3)(x+5) ans.
2007-03-30 11:42:17 · answer #8 · answered by snowman 2 · 1⤊ 0⤋
(x-3)(x+5)
Check:
x^2+5x-3x-15
x^2+2x-15
2007-03-30 11:28:48 · answer #9 · answered by Anonymous · 4⤊ 0⤋