Time Dilation Physics?

Question

A spacecraft has a nonrelativistic (or classical) momentum whose magnitude is 1.80 x 10^13 kg*m/s. The spacecraft moves at such a speed that the pilot measures the proper time interval between two events to be one-half the dilated time interval. Find the relativistic momentum of the spacecraft.

Answer 1

Proper time is always the time measured by an observer moving along with the clock.

Time dialation is given by:

(delta)t=(gama)(delta)t'

where: (gama)=1/{[1-(v^2)/c^2)]}^.5
t'=accelerated frame
t=stationary frame

so for your problem (gama)=1/2

i.e 1/2={[1-(v^2)/c^2)]}^.5

solve for v

Answer 2

Lifetime measured in the international = (2.6x10^-8) / sqrt(a million-v^2/c^2) = a million.3 x 10^-9 Distance = vt = 0.ninety 8 * 3x10^8 *a million.3 x 10^-7 = 40 8.2 kilo meters w/o time dilation: distance = 0.ninety 8 * 3 x 10^8 * 2.6 x 10^-8 = 9.6 kilo meters that different guy replaced into quite incorrect you didnt share the solutions inclusive of your friends did you................... properly with the intention to lend you a hand i might would desire to diminish off my very own jk yet with the intention to try this you'll desire to play a speedy interest of spoons whilst in the physics lab if coach significant isn't there nathan damn nathan superb questioning nevertheless, asking yahoo solutions to help us out

Answer 3

Clearly high school special relativity should be limited
to the framed picture of Albert Einstein hanging on the wall.

Answer 4

Hi. You can't. One phenomenon is that the measuring tools and clocks distort at the same ratio.