How would I go about this problem?

Question

I need help getting started. Thank you.

A container contains 2 red, 3 white, and 5 yellow balls. Suppose that once a ball is drawn it is not replaced. What is the probability that 2 red balls will be drawn in 2 tries?

Answer 1

(2/10)*(1/9)

possible ways of taking a red ball the first time is 2 ways , divided this by the total possible ways of taking any ball.

next given that one ball is taken, think again :
possible ways of taking 1 red ball ( there is only one red left ) out of 9 balles