(x+1) (x^2+3)
2007-03-30 09:20:48 · 8 answers · asked by stu_art_27 2 in Science & Mathematics ➔ Mathematics
x^3 + x^2 + 3x + 3
x^2(x + 1) + 3(x + 1)
(x + 1)(x^2 + 3)
2007-03-30 09:24:13 · answer #1 · answered by Mathematica 7 · 1⤊ 0⤋
x^3 + x^2 = x^2(x + 1)
3x + 3 = x(x + 1)
Add the two statements and get:
x^3+x^2+3x+3 = (x+1) (x^2+3)
2007-03-30 09:26:05 · answer #2 · answered by Amit Y 5 · 1⤊ 0⤋
x^3 + x^2 + 3x + 3
(x^3 + x^2) + (3x + 3)
x^2(x + 1) + 3(x + 1)
(x^2 + 3)(x + 1)
Correct
2007-03-30 09:25:54 · answer #3 · answered by Sherman81 6 · 1⤊ 0⤋
x^3 + x^2 + 3x + 3
x^2(x + 1) + 3(x + 1)
(x + 1)(x^2 + 3)
It is like this because when u have to the third power you look at them separately inside of the second power where you actually FOIL
2007-03-30 09:34:52 · answer #4 · answered by Becky 2 · 1⤊ 0⤋
Factor by grouping:
x^2(x+1)+3(x+1)
(x+1)(x^2+3)
That is correct!
2007-03-30 09:50:24 · answer #5 · answered by Anonymous · 0⤊ 0⤋
(x+1) (x^2+3)
Using foil,
x^3 + 3x + x^2 + 3 = x^3 + x^2+ 3x + 3
So yes, it is correct.
2007-03-30 09:25:08 · answer #6 · answered by lamb.chops 2 · 1⤊ 0⤋
correct
=x^2(x+1)+3(x+1)
=(x+1)(x^2+3)
2007-03-30 09:26:38 · answer #7 · answered by Reema 1 · 1⤊ 0⤋
ding dong
2007-03-30 09:43:31 · answer #8 · answered by gjmb1960 7 · 1⤊ 0⤋