Write the following as one logarithm with a coefficient of 1:
3log x+ log y - 2log r - log t
2007-03-30 08:36:12 · 4 answers · asked by jrnitro123 1 in Science & Mathematics ➔ Mathematics
3log x+ log y - 2log r - log t
log x^3+ log y - (log r^2 + log t)
log (x^3 * y) - [log (r^2 * t)]
log [(yx^3)/(tr^2)]
2007-03-30 08:40:46 · answer #1 · answered by Mathematica 7 · 0⤊ 0⤋
3log x+ log y - 2log r - log t
=log yx^3 -log(tr^2)
= log(yx^3/tr^2)
2007-03-30 08:42:26 · answer #2 · answered by ironduke8159 7 · 0⤊ 0⤋
hiya log and Ln are 2 diffrent words. base of log is 10 and base of Ln is e(exponential). for Ln (y) – Ln (y-4) = Ln (2) => Ln [y/(y-4)] = Ln (2) taking antilog the two facets we get y/(y-4)=2 => y=2y-8 => y=8
2016-12-15 12:22:09 · answer #3 · answered by Anonymous · 0⤊ 0⤋
logx^3 + logy -logr^2 -logt
log(((x^3)*y)/((r^2)(t))
2007-03-30 08:42:51 · answer #4 · answered by w1ckeds1ck312121 3 · 0⤊ 0⤋