For exponential growth, you need the x as an exponent.
From the way you have it written, none of them show x as an exponent. So, I'd say NONE.
2007-03-30 08:35:09
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answer #1
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answered by Mathematica 7
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If you meant this:
a.y=(1/2)^x
b.y=(1/4)^x
c.y=(1/2)^(2x)
d.y=2^x
then only d is exponential growth. You don't need a negative exponent to be decay, you can also have a base between 0 and 1, which the other 3 choices have, making them all decay. If this isn't what you meant, then fix your question and we can stop guessing and get it right :-)
2007-03-30 09:02:03
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answer #2
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answered by Kathleen K 7
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i'm afraid you're all incorrect. A, B and D are linear applications. i'm assuming that for the time of C you recommend (a million/2)^(2x) and not what you wrote (in any different case C is likewise linear). If that's what you meant, than C is exponential, yet no longer advance. It truthfully decreases exponentially.
2016-12-08 14:39:40
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answer #3
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answered by ? 4
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I'd say c since I think you meant the 2x to be an exponent. The rest are all linear.
2007-03-30 08:38:24
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answer #4
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answered by ironduke8159 7
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if by "c" you mean
y = (1/2)^(2x)
then C. is the answer.
y = ax^r is exponential growth
y = ax^(-r) is exponential decay.
2007-03-30 08:36:43
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answer #5
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answered by Sherman81 6
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prety sure none of them are
2007-03-30 08:35:58
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answer #6
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answered by w1ckeds1ck312121 3
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