Write the conjugate pair to the acids and bases.
a) PO4^-3 (charge of -3)
b) H2S
c) NH3
d) C3H5O2^-1 (charge of -1)
2007-03-30 08:17:03 · 4 answers · asked by Anonymous in Science & Mathematics ➔ Chemistry
Add H+ to a, c and d, and take H+ off b.
I'll do one for you: NH3 + H+ -----> (NH4)+
2007-03-30 08:22:28 · answer #1 · answered by Gervald F 7 · 0⤊ 0⤋
a) PO4-3 + H+ <--> HPO4-2
b) H2S <--> 2H+ + S-2
c) NH3 + H2O <--> NH4+ + OH-
d) C3H5O2- + H+ <--> C3H5COOH
conjugate acid of PO4-2 is HPO4-2
conjugate base of H2S is S-2
conjugate acid of NH3 is NH4+
conjugate acid of C3H5O2- is C3H5COOH
2007-03-30 08:24:50 · answer #2 · answered by Dr Dave P 7 · 0⤊ 0⤋
PO4^3-(aq) + H2O(l) --> HPO4^2-(aq) + OH-(aq)
H2S + H2O(l) --> HS-(aq) + H3O+(aq)
NH3(aq) + H2O(l) --> NH4+(aq) + OH-(aq)
C3H5O2-(aq) + H2O(l) --> C3H6O2(aq) + OH-(aq)
so
a) HPO4^2-
b) HS-
c) NH4+
d) C3H6O2
2007-03-30 08:27:40 · answer #3 · answered by lifeaura18 2 · 0⤊ 0⤋
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2014-11-13 15:13:51 · answer #4 · answered by ? 3 · 0⤊ 0⤋