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(x+2)/(x^2-1) , (x+2)/(x^2+2x+1) , (x+2)/(x+1)

2007-03-30 07:15:27 · 3 answers · asked by Anonymous in Science & Mathematics Mathematics

3 answers

(x+1)(x+1)(x-1)

the denom for the first eqn is (x+1)(x-1)
for the second its (x+1)(x+1)
for the third its (x+1)

the simplest way to make them all equal is to make them all
(x+1)^2 (x-1)

2007-03-30 07:19:56 · answer #1 · answered by davidosterberg1 6 · 0 0

(x-1)(x+1)^2

2007-03-30 14:18:38 · answer #2 · answered by tedfischer17 3 · 0 0

(x+1) (x+1)(x-1)

2007-03-30 14:27:04 · answer #3 · answered by Dave aka Spider Monkey 7 · 0 0

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