the equation 2x^3+ 3x^2 -18x-27=0 has ___ solutions?

Question

1
2
3
0

Answer 1

All equations have solutions. They may not have real solutions but they all have at least complex solutions

By inspection one root is x = 3
Thus 2x^3+ 3x^2 -18x-27 = (x -3)(2x^2 +9x +9)
= (x -3)(x + 3)(2x + 3) the other roots being x = -3 and x = -3/2

Answer 2

3. This is a third order function, and the order of the function will also define the number of real y intercepts that the function has. There may be some imaginary (I don't believe that this function has any imaginary solutions however).

The order of the function is determined by the highest exponent expressed in the function that does not have a coefficient of zero.

Answer 3

2x^3 + 3x^2 - 18x - 27
(2x^3 + 3x^2) + (-18x - 27)
x^2(2x + 3) - 9(2x + 3)
(x^2 - 9)(2x + 3)
(x - 3)(x + 3)(2x + 3)
x = 3, -3, or (-3/2)

ANS : 3 solutions

Answer 4

At least one solution... Could have a double root (thus two solutions) or a pair of complex roots (thus one real solution). Or it could have three....

Try graphing it? Or use the rational zeros theorem to see if you can figure them out?

Answer 5

3 because the largest power of x is 3.

Answer 6

3
This is a cubic equation.
It has three roots.
3, -3, -3/2.

Answer 7

simple a third order equation has at least three real solutions

Answer 8

the equatioin's got three unkwowns which are
1. x = 3
2. x = -3
3. x = -1.5

Answer 9

3 x-zeros infinite solutions

Answer 10

3 roots

-1.5
+/- 3