Slope question?

Question

determine the equation of the line that passses through the point (3,9) and is parrell to to the line 8y-40x=4 write in slope intercept form

Answer 1

first write your original line is slope-intercept form

Now that you know the slope of your original line you can say what the slope is of your new line (the one you want the equation for). ie. you know M

Then you have a point P(3,9) which satisfies this new equation and so you can work out your new Y-intercept.

So y = (40x+4)/8
or y = 5x +1/2

New line is y = Mx + B where M is slope (5) and B is the new y intercept

9 = 5(3) + B

B = 9-15 = -6

New line is: y = 5x - 6

Answer 2

The line 8y-40x = 4 has a slope of 5
Thus the slope of the desired line must also have a slope of 5
So y = 5x + b
Since the line passes through (3,9), we have:
9=5(3) +b
b= -6
So equation is y= 5x -6

Answer 3

well heres how you do it

since the line is parrellel to 8y-40x=4, then the slope of the line in question is equal to the line you currently are given

so you have find the slope of 8y-40x=4

heres how you do it:

8y-40x=4 -----> 8y=40x+4 (i added 40x to both sides to isolate the Y variable)

now divide

(8y/8) = (40x+4)/8

y=5x + (1/2)

so the slope of your line is 5

now that you have the slope of the line you can use the equation
y-y1=m(x-x1) to find the equation of the line you are looking for

and you know the coordinates (3,9) where 3 is x1 and 9 is y1

so

y-9=5(x-3)
y-9=5x-15

subtract 9 from both sides to isolate y

y=5x-6

that is your answer to the line you are looking for

again: y=5x-6 is the equation of the line

Answer 4

The slope of 8y - 40x = 4 is: 5.

8y = 40x + 4
y = 5x + 1/2

(y - 9) = 5(x-3)
y - 9 = 5x - 15
y = 5x - 6

Answer 5

Eq. of the other line is 8y-40x=4
or, 8y=40x+4
or, y=(40/8)x+4/8
or, y=5x+1/2
Thus,
m2=5
As we know that in case of parallel lines slope of the first line is equal to the second line,
threfore,
m1=m2=5
The given point is (3,9) hence,
y=mx+c
or, 9=5*3+c
or, c=9-15
or, c=-6
Therefore, the equation of the line that passes through the point (3,9) is y=5x-6(--y=mx+c; m=5 and c=-6--).

Answer 6

8y-40x=4
y=5x+0.5

So the slope of this line is 5

The slope of the other line is also 5
y=5x+c

Substitute in the point x=3, y=9
9=5*3 + c

c=-6

So your line is y=5x-6

Answer 7

8y - 40x = 4
8y = 40x + 4
y = 5x + 1/2
Gradient is m = 5
Line thro`(3,9) with m = 5 is:-
y - 9 = 5.(x - 3)
y - 9 = 5x - 15
y = 5x - 6
or , if desired:-
5x - y - 6 = 0

Answer 8

y=40/8(x-3)+9 = 5x - 6

Answer 9

i don't remember exactly, but if you rewrite the equation you already have, you will get: y= 5x + 1/2
a parallel line will have the same slope (5)

then you need another equation, but I can't remember it-sorry

Answer 10

y = 5x - 6