9x^2 + 3 (2x - x^2) + 11x = 6x^2 + 17x
2007-03-30 04:42:15 · 10 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
True
9x² + 3(2x - x²) + 11x = 6x² + 17x
9x² + 6x - 3x² + 11x = 6x² + 17x
6x² + 17x = 6x² + 17x. . . .Both sides of the equation equal each other
6x² + 17x - 6x² = 6x² + 17x - 6x²
17x = 17x
17x - 17x = 17x - 17x
0 = 0
- - - - - - - - - -s-
2007-03-30 05:04:53 · answer #1 · answered by SAMUEL D 7 · 0⤊ 0⤋
True. Let us see how:
9 x^2 + 3(2x - x^2) + 11 x = 9x^2 + 6x - 3 x^2 + 11 x
= 9 x^2 - 3 x^2 + 6x + 11 x = 6 x^2 + 17 x = RHS of the equation
So, the equation is true.
2007-03-30 04:48:22 · answer #2 · answered by Swamy 7 · 0⤊ 0⤋
9x^2 + 3 (2x - x^2) + 11x = 6x^2 + 17x
9x^2 +6x -3x^2 +11x = 6x^2 +17x
6x^2 +17X =6x^2 + 17x
True
2007-03-30 04:47:15 · answer #3 · answered by ironduke8159 7 · 0⤊ 0⤋
if you distribute the stuff in the parenthesis (multiply 3 by 2x and 3 by -x^2), you will find that the left side of the equation changes to: 9x^2 + 6x -3x^2 + 11x. the right side stays the same and when you combine like terms on the left side (all the x^2 with each other and the x's with each other), you'll see that both sides of the equation are equal.
the answer is true
2007-03-30 04:49:45 · answer #4 · answered by ANT-a-gonistic 3 · 0⤊ 0⤋
9x^2 + 6x - 3x^2 + 11x = 6x^2 +17x ?
6x^2 + 17x = 6x^2 + 17x yes, true
2007-03-30 04:47:50 · answer #5 · answered by Anonymous · 0⤊ 0⤋
9x^2 + 3 (2x - x^2) + 11x
= 9x² + 6x - 3x² + 11x
= 6x² + 17x
True
2007-03-30 04:45:28 · answer #6 · answered by MamaMia © 7 · 0⤊ 0⤋
true
LHS
9x^2 + 3 (2x-x^2) + 11x
9x^2 + 6x-3x^2 +11x
6x^2 + 17x
LHS = RHS
hence verified.
2007-03-30 05:04:16 · answer #7 · answered by pritamgola 2 · 0⤊ 0⤋
True
2007-03-30 04:45:49 · answer #8 · answered by gebobs 6 · 0⤊ 0⤋
TRUE...true...true........True
2007-03-30 04:54:52 · answer #9 · answered by b_ney26 3 · 0⤊ 0⤋
TRUE
2007-03-30 04:45:52 · answer #10 · answered by tuoidabuon 2 · 0⤊ 0⤋