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9 answers

1,2,3,4,6,8,12,16,24,48

1*48
2*24
3*16
4*12
6*8

I'm assuming you mean integers here, and not all rational numbers, which would provide an infinite set of solutions.
(e.g. 0.5*96, etc)

2007-03-30 04:42:36 · answer #1 · answered by MamaMia © 7 · 1 0

48 = 48 X 1, 24 X 2, 16 X 3, 12 X 4, 8 X 6, 6 X 8,
3 X 2 X 2 X 2 X 2 X 1

2007-03-30 11:45:17 · answer #2 · answered by Swamy 7 · 0 0

Easiest way to do this is list all the factors of 48, which would be...
1,2,3,4,6,8,12,16,24,48
Now multiply the first and last terms
Then multiply the second term with the second to last term
Then multiply the third term with the third to the last term, etc.
You can also have something like 2*4*6, or 2*3*8

2007-03-30 11:49:37 · answer #3 · answered by Ohioguy95 6 · 0 0

3 X 16

2007-03-30 11:43:37 · answer #4 · answered by Anonymous · 0 0

Factor out 48 to its most common terms.
2 x 3 x 2 x 2 x 2 x 1

Then group them together and you can find your answer.
like 2 x (3 x 2 x 2 x 2 x 1) = 2 x 24

Hope this helps. Good Luck!

2007-03-30 11:44:40 · answer #5 · answered by Hbluegal 2 · 0 0

that is called FACTORING, and it is one of the most difficult tasks in mathmatics.

Sure for a small number like 48, its easy to work it out, but for really huge numbers it can take thousands of years.

This is the basis for PUBLIC KEY cryptography. A secret code is multiplied by a very big prime number multiplied by the multiplicand of that prime and another prime. Only by knowing the other prime (called the secret key) can this huge number be decoded.

If a simple method of factoring were to be discovered, much of public key cryptography (think: secure web pages) would be rendered useless.

2007-03-30 11:54:54 · answer #6 · answered by disco legend zeke 4 · 0 0

2*24

4*12

6*8

1*48

i think thats it

2007-03-30 11:43:06 · answer #7 · answered by fountain_of_knowledge 2 · 0 1

2X24
3X16
4X12
6X8

integers did you say?



//

2007-03-30 12:45:12 · answer #8 · answered by Anonymous · 0 0

1,2,3,4,6,8,12,16,24,48

2007-03-30 11:43:13 · answer #9 · answered by gebobs 6 · 0 0

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