try formula of (a+b)^2
ie [(square root of 7) - (square root of 2)]^2
=root(7)^2 -2sqrt(7*2) + root(2)^2
=7+2-2sqrt(14)
=9 -2sqrt(14)
=1.5166852264521172288325025353669
2007-03-30 03:38:46
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answer #1
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answered by JJ 4
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Treat this as a quadratic equation and multiply it out. What I mean is that you can write this as (x - y)^2, where x = sqrt(7) and y = sqrt(2).
You know that (x - y)^2 = x^2 - 2xy + y^2.
When you square a square root, you get the original number, so you can plug back in for x and y:
7 - 2 * sqrt(7) * sqrt(2) + 2
When multiplying square roots, you can multiply what is under the radical sign. So you end up with:
9 - 2 * sqrt(14)
2007-03-30 03:36:09
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answer #2
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answered by Rev Kev 5
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[(square root of 7) - (square root of 2)]squared
=7 -2sqrt(7*2) +2
=9 -2sqrt(14)
2007-03-30 03:36:29
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answer #3
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answered by ironduke8159 7
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(sqrt7 -sqrt 2)^2
= (2.645751311- 1.414213562)^2
= 1.516686
Forgot about all these irrational roots.
2007-03-30 03:41:57
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answer #4
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answered by The exclamation mark 6
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[(sqrt 7) - (sqrt 2)]^2
(sqrt 7 - sqrt 2)(sqrt 7 - sqrt 2)
(sqrt 7)(sqrt 7) - 2(sqrt 7)(sqrt 2) + (sqrt 2)(sqrt 2)
7 - 2 sqrt 14 + 2
9 - sqrt 14
2007-03-30 03:41:55
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answer #5
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answered by Cindy 2
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I can't believe how many people got this wrong.
(sqrt(7)-sqrt(2))^2 = 1.516685
2007-03-30 03:40:47
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answer #6
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answered by Fuller 3
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(sqrt(7)-sqrt(2))^2
=7+2-2sqrt(14)
=9-2sqrt14
2007-03-30 03:36:00
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answer #7
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answered by Anonymous
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([7^(1/2)] - [2^(1/2)]) ^2 = (2.6458-1.4142) ^2
= (1.24) ^ 2
= 1.52 to 2 decimal places
2007-03-30 03:43:52
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answer #8
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answered by wolfie 1
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That would be around (2.646 - 1.414)^2
= 1.232^2 = 1.518
2007-03-30 03:38:03
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answer #9
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answered by Ohioguy95 6
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(sq rt 7- sq rt 2) (sq rt 7-sq rt 2)
Foil
7- 2 (sq rt 2) (sq rt 7) +2
2007-03-30 03:36:39
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answer #10
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answered by spychic19 4
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