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what is: [(square root of 7) - (square root of 2)]squared?

2007-03-30 03:31:48 · 11 answers · asked by Anonymous in Science & Mathematics Mathematics

11 answers

try formula of (a+b)^2
ie [(square root of 7) - (square root of 2)]^2
=root(7)^2 -2sqrt(7*2) + root(2)^2
=7+2-2sqrt(14)
=9 -2sqrt(14)
=1.5166852264521172288325025353669

2007-03-30 03:38:46 · answer #1 · answered by JJ 4 · 0 0

Treat this as a quadratic equation and multiply it out. What I mean is that you can write this as (x - y)^2, where x = sqrt(7) and y = sqrt(2).

You know that (x - y)^2 = x^2 - 2xy + y^2.

When you square a square root, you get the original number, so you can plug back in for x and y:

7 - 2 * sqrt(7) * sqrt(2) + 2

When multiplying square roots, you can multiply what is under the radical sign. So you end up with:
9 - 2 * sqrt(14)

2007-03-30 03:36:09 · answer #2 · answered by Rev Kev 5 · 0 2

[(square root of 7) - (square root of 2)]squared
=7 -2sqrt(7*2) +2
=9 -2sqrt(14)

2007-03-30 03:36:29 · answer #3 · answered by ironduke8159 7 · 0 0

(sqrt7 -sqrt 2)^2

= (2.645751311- 1.414213562)^2

= 1.516686

Forgot about all these irrational roots.

2007-03-30 03:41:57 · answer #4 · answered by The exclamation mark 6 · 1 0

[(sqrt 7) - (sqrt 2)]^2
(sqrt 7 - sqrt 2)(sqrt 7 - sqrt 2)
(sqrt 7)(sqrt 7) - 2(sqrt 7)(sqrt 2) + (sqrt 2)(sqrt 2)
7 - 2 sqrt 14 + 2
9 - sqrt 14

2007-03-30 03:41:55 · answer #5 · answered by Cindy 2 · 0 0

I can't believe how many people got this wrong.

(sqrt(7)-sqrt(2))^2 = 1.516685

2007-03-30 03:40:47 · answer #6 · answered by Fuller 3 · 1 0

(sqrt(7)-sqrt(2))^2
=7+2-2sqrt(14)
=9-2sqrt14

2007-03-30 03:36:00 · answer #7 · answered by Anonymous · 0 0

([7^(1/2)] - [2^(1/2)]) ^2 = (2.6458-1.4142) ^2
= (1.24) ^ 2
= 1.52 to 2 decimal places

2007-03-30 03:43:52 · answer #8 · answered by wolfie 1 · 0 0

That would be around (2.646 - 1.414)^2
= 1.232^2 = 1.518

2007-03-30 03:38:03 · answer #9 · answered by Ohioguy95 6 · 1 0

(sq rt 7- sq rt 2) (sq rt 7-sq rt 2)

Foil

7- 2 (sq rt 2) (sq rt 7) +2

2007-03-30 03:36:39 · answer #10 · answered by spychic19 4 · 0 0

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