How many moles of bromide ions (Br-) are there in 662 mL of a 0.349 M solution of calcium bromide (CaBr2)?
2007-03-30 03:07:46 · 4 answers · asked by Anonymous in Science & Mathematics ➔ Chemistry
Molarity = moles/L
0.349 = moles / 0.622
Moles CaBr2 = 0.217
CaBr2 >> Ca2+ + 2 Br-
Moles Br- = 2 (0.217)=0.434
2007-03-30 03:14:08 · answer #1 · answered by Anonymous · 0⤊ 0⤋
Molarity (M) = mole/liter
mole= Mloarity(M) * liter
Convert 662ml to liter
662ml = 1l/1000ml = 0.662l
mole = 0.349M * 0.662l = 0.231mol
so bromide ion (Br) as 0.231mol
2007-03-30 10:59:59 · answer #2 · answered by Wonder 2 · 0⤊ 0⤋
Ca(Br)2---> Ca++ + 2Br-
1L of Ca(Br)2 contains 0.349mole
662mL = 0.662 contains 0.662 *0.349 =0.231 mole of Ca(Br)2
and as 1 mole of Ca(Br)2 gives 2 Br -
there are 0.231*2 =0.462 mole of Br-
2007-03-30 10:32:54 · answer #3 · answered by maussy 7 · 0⤊ 0⤋
Is it an aqueous solution? If so, then there are 0.462 moles Br-.
2007-03-30 10:15:45 · answer #4 · answered by nihil nonscio 2 · 0⤊ 0⤋