2007-03-30 02:09:27 · 9 answers · asked by bee 1 in Science & Mathematics ➔ Mathematics
4x² + 3x + 0 - 0
4x² + 3x + 0 - 0 = 0 - 0
4x² + 3x = 0
x(4x + 3) = 0
- - - - - - - s-
2007-03-30 02:37:53 · answer #1 · answered by SAMUEL D 7 · 1⤊ 0⤋
If you've typed this question out correctly why have you put the extra +0 in - is that the correct number? normally quadratic questions have a number there - not a zero
Anyway I will solve it for you as is
4x^2 + 3x = 0
x(4x + 3) = 0
so either x = 0
or 4x+3=0
4x=-3
x=-3/4
so the solutions are x = 0 or x = -3/4
2007-03-30 02:22:52 · answer #2 · answered by hey mickey you're so fine 3 · 1⤊ 0⤋
4x^2 +3x = 0
x(4x +3) = 0
x=0 and
4x = -3
x=-3/4
the solutions are 0 and -3/4
2007-03-30 03:15:00 · answer #3 · answered by bignose68 4 · 1⤊ 0⤋
4x^2 + 3x +0 = 0
4x^2 + 3x = 0
x (4x + 3) = 0
The solutions are : x = 0 and x = -3/4
2007-03-30 03:06:28 · answer #4 · answered by Bharat 4 · 1⤊ 0⤋
4x² + 3x + 0 = 0
4x² + 3x = 0
x (4x + 3) = 0
x = 0
or
4x + 3 = 0
4x = -3
x = -3/4
2007-03-30 02:35:35 · answer #5 · answered by deniseholton 2 · 1⤊ 0⤋
4X^2 + 3x + 0 = 0
x(4x + 3) = 0
x = 0
4x + 3 = 0
4x = -3
x = -3/4
So, the solutions are x = 0, -3/4
2007-03-30 02:20:16 · answer #6 · answered by JOhn M 5 · 1⤊ 0⤋
just substitue an x out.
x(4x+3)
either x=0 or 4X+3=0 then solve for x
X=-3/4
2007-03-30 02:19:41 · answer #7 · answered by Anonymous · 1⤊ 0⤋
x = 0?
2007-03-30 02:19:36 · answer #8 · answered by firstythirsty 5 · 0⤊ 0⤋
4x^2+3x=0
x(4x+3)=0
x=0 or -3/4
2007-03-30 04:09:16 · answer #9 · answered by Anonymous · 0⤊ 0⤋