Usually yes. Since it's a quadratic equation. But sometimes you may get only 1 value for x, and that's when you're able to factorise the equation into the form ( x +/- b )^2 = 0
2007-03-29 21:34:23
·
answer #1
·
answered by Willy 2
·
0⤊
0⤋
x=0
2007-03-29 22:32:28
·
answer #2
·
answered by Boadu K 1
·
0⤊
0⤋
Then 4x^2+3y0=0
or (2x)^2 +3y0=0
There are many possible solutions. All with varying values of y. X however, is always 0.
x=0,y=any number
2007-03-29 22:29:38
·
answer #3
·
answered by Raider 3
·
0⤊
0⤋
better to learn the nuts and bolts of how it's done than to memorize formulas (besides checking what you've typed before submitting)
you don't need a formula since this is a very simple equation, simply factor it to
x(4x + 3) = 0, this tells you either
x = 0, or 4x + 3 = 0 => 4x = -3 => x = -3/4.
2007-03-29 21:58:20
·
answer #4
·
answered by kozzm0 7
·
0⤊
0⤋
Yeah. What is that last zero doing there? It nullifies the whole project. If 4x^2 = 0, x can only be 0, which doesn't carry two values.
2007-03-29 21:38:18
·
answer #5
·
answered by obelix 6
·
0⤊
0⤋
0 and -0.75.
This is a quadratic equation. You can solve it using the quadratice formula, or do it the real world way by using an advanced calculator.
2007-03-29 21:37:09
·
answer #6
·
answered by Jim M 3
·
0⤊
0⤋
yes
2007-03-29 21:56:35
·
answer #7
·
answered by wendy9448580 2
·
0⤊
0⤋
may be
2007-03-29 21:36:36
·
answer #8
·
answered by gansatanswers 3
·
0⤊
1⤋