2007-03-29 19:27:39 · 6 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
Yeah, +0 and -0, ha ha.
The only way it can possible have two solutions in x is if it was:
4x²+3x=0
in which case the solutions would be x=0, x= -3/4
(In the unlikely event that you actually meant what you wrote, you get two imaginary answers, where i =√(-1):
4x²+3x^0=0
4x² = -3
x² = -3/4
x = ±(√3)i/2 where i =√(-1)
2007-03-29 19:38:31 · answer #1 · answered by smci 7 · 0⤊ 0⤋
4x^2 + 3x = 0 can be rewritten as:
(x) * (4x + 3) = 0
x=0 is the obvious value, and the other value is found when you set 4x + 3 = 0, or x = -3/4
2007-03-30 02:39:55 · answer #2 · answered by halofan5 2 · 0⤊ 0⤋
is it 3X0 or 3x?
i think it shud be 4x^2+3x=0
this would give: x(4x+3)=0; x=0 and 4x+3=0
i.e x= -3/4;
therefore, x=0 and -3/4
2007-03-30 02:40:00 · answer #3 · answered by intrigued 2 · 0⤊ 0⤋
Assume equation is :-
4x² + 3x = 0
x.(4x + 3) = 0
x = 0, x = - 4/3
2007-03-30 05:51:30 · answer #4 · answered by Como 7 · 0⤊ 0⤋
Zero.
2007-03-30 02:34:13 · answer #5 · answered by big head 1 · 0⤊ 0⤋
zero
2007-03-30 02:31:44 · answer #6 · answered by Karthik 1 · 0⤊ 0⤋