Hydrochloric acid can be prepared using the reaction described by the chemical equation: 2 NaCl(s) + H2SO4(l) ----> 2 HCl(g) + Na2 SO4(s). How many grams of HCl can be prepared from 393 g of H2SO4 and 4.00 moles of NaCl?
2007-03-29 19:19:22 · 2 answers · asked by crazymonkey 1 in Science & Mathematics ➔ Chemistry
1. work out 393/98 (moles of H2SO4)
2. halve the moles of NaCl to 2.
3. which is greater?
4. the other is the limiting reagent. Multiply it by 2, and then by 36.5 to get grams of HCl.
2007-03-29 19:28:48 · answer #1 · answered by Gervald F 7 · 1⤊ 0⤋
based on the equation,
1 mole of H2SO4 gives 2 Moles of HCl
Actually,
moles of H2SO4393/((1*2)+(32)+(16*4))=4 moles of H2SO4
so, 4 moles of H2so4 gives 8 moles of HCl
using the formula mass=molecular mass x Mole,
mass = (35.5+1)*8 moles of HCl
mass=292 g
thus, 292 grams of HCl can be prepared
2007-03-30 02:41:25 · answer #2 · answered by Anonymous · 0⤊ 1⤋