What is the difference in the force....?

Question

experienced by a cubic meter of water due to the Moon's gravitational pull when the Moon is on the same side of the Earth as the water and when the Moon is on the opposite side of the Earth as the water? (About 12 hours later) What is the force of the Earth's gravity on that quantity of water (i.e. it's weight)?

Answer 1

orbit: 384,400 km from Earth
diameter: 3476 km
mass: 7.35e22 kg
G = 6.6742*10^-11 Nm^2/kg^2
diameter of Earth = 12,756.32 kilometers
F1 = (6.6742*10^-11 Nm^2/kg^2)(1 m^3)(10^6 cm^3/m^3)(10^-3 kg/cm^3)(7.35*10^22 kg)(1 km^2/10^6 m^2)/(384,400 - 6,378.16)^2
F1 = 0.034328 N

F2 = (6.6742*10^8)(7.35)/(384,400 + 6,378.16)^2 N
F2 = 0.032123 N

W = (1 m^3)(10^6 cm^3/m^3)(10^-3 kg/cm^3)(9.80665 m/s^2
W = 9,806.65 N
∆F = 0.002205 N
∆F = 0.000022485%