Can someone explain step-by-step how to do "([3^33x^23y^-43]^0)^3" please?

Question

I'm not certain what to do....but is the answer 3^99x^69y^-129?

Answer 1

No: note that you have ([stuff]^0)^3.
[stuff]^0 = 1
1^3 = 1.
So the answer is 1.

Answer 2

I can believe I actually worked out this problem haha. Ok, the way I see it is my professor told me that anything raised to the power of 0 is 1. Therefore, the quanitiy you are given in your brakets is one since it is raised to a zero power. I will re-write the equation as this.

(1)^3

I assume that you know that one to the power of 3 obviously equals one; therfore, the only solution I could come up with is 1.

If I am correct, then the only purpouse of giving you an equation such as this one is to get you to remember. Any quantity raised to the zero power is one. Take note of that I am sure they will put a question like that on an exam.

Remember, 50% of the key to understanding mathematics is not to over think a problem.

I hope this helps, and I encourage you to dubble check my answer with someone elses to make sure I am correct. If not I apologize in advance.

Have a nice day!

Answer 3

I think the answer is ............ 1

the stuff in the square brackets [3^33x^23y^-43] is all raised to the 0 power. Anything raised to the zero power is 1. Tht results in (1)^3 which equals 1.