Can someone people help me and show me HOW to factor this equation:
24x^3+18x^2
Key-- ^__ any number means to the power of (as you know)
2007-03-29 15:49:47 · 5 answers · asked by R 1 in Science & Mathematics ➔ Mathematics
take out 6x^2
6x^2 (4x + 3)
2007-03-29 15:55:20 · answer #1 · answered by 7 · 1⤊ 1⤋
First get rid of x^2 and 6.
6x^2(4x + 3) = 0
so if we pay attention to only one section we can say that;
6x^2 = 0 , so x = 0 on two opccations
also that
4x +3 = 0 so
4x = -3
x = -3/4
2007-03-29 22:57:33 · answer #2 · answered by Anonymous · 0⤊ 1⤋
Factor out a 6x^2:
6x^2(4x+3)
2007-03-29 22:56:45 · answer #3 · answered by Anonymous · 0⤊ 0⤋
24x^3 + 18x^2 = 6x^2(4x + 3).
STEP ONE: find the GCF (Greatest Common Multiple with is 6, so = 6(4x^3+ 3x^2)
STEP TWO" factor out the largest "x" exponent you can ge (in this case x^2, so attach it to the 6 already outside parenthesis.). so......
ANSWER: 6x^2(4x + 3).
PROOF (6x^2) x (4x) = 24x^3 and (6x^2) x (3) = 18x^2
Hope this helped.
2007-03-29 23:12:15 · answer #4 · answered by njmarknj 5 · 0⤊ 1⤋
6x^2(4x+3)
2007-03-29 22:53:47 · answer #5 · answered by bruinfan 7 · 1⤊ 2⤋