plz help me
2007-03-29 15:40:46 · 5 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
Haven't you heard that a line perpendicular to a line with slope m has a slope of - 1/m? So, the equation of the line has a slope of -1/3 (the given equation is in slope-intercept form). To find the intercept of the perpendicular line, Take the equation y = -x/3 + b, where b is unknown, and substiute x=6 and y=-2 in. That's your answer.
2007-03-29 15:46:05 · answer #1 · answered by cattbarf 7 · 1⤊ 0⤋
A line perpendicular to another line has a slope equal to the negative inverse of the slope of the original line.
In this case, the slope is 3. Therefore, the perpendicular must have a slope of -1/3.
now, using the point/slope formula with the point that you want the line to go through, you get
y+2 = -1/3(x-6)
3y + 6 = -x +6
y= -1/3x
2007-03-29 22:47:21 · answer #2 · answered by bz2hcy 3 · 1⤊ 0⤋
ok the other line is perpendicular, so...
you use (1/3) as a slope.
so its:
y= (1/3)x + b
(6, -2)
x y
then plug in x and y
-2 = (1/3)(6) + b
-2 = 2 + b
-2-2=b
-4 = b
so...
y = (1/3)x -4
2007-03-29 22:50:06 · answer #3 · answered by C12H22O11 4 · 0⤊ 0⤋
The perpendicular of slope 3 is -1/3
Use the point-slope form:
y-y1=m(x-x1)
y+2=-1/3(x-6)
y+2=-1/3x+2
y=-1/3x
I hope this helps!
2007-03-29 22:53:46 · answer #4 · answered by Anonymous · 0⤊ 0⤋
grad of perp = -1/3
sub (6,-2) into y=mx+c
-2=-1/3(6)+c
c= 0
therefore, eqn is y= -1/3x
2007-03-29 22:48:12 · answer #5 · answered by yuk 2 · 1⤊ 0⤋