I need help on my math problems, its just really hard?

Question

Solving Equations and use the quadratic formula to solve the equation.
1. 4xsquared - 13x + 3=0
any help?

Answer 1

1)

4x^2 - 13x + 3 = 0

One method of solving this is using the "ac" method. For
ax^2 + bx + c = 0, first multiply a and c. a = 4, c = 3, so
ac = 12.

Next, find two factors of 12 which add up to the middle coefficient, -13. The answer to that is -12 and -1.

Now, split -13x into -12x and -x (as per what was just said).

4x^2 - 12x - x + 3 = 0

Here's where we group each pair of terms.

4x(x - 3) - (x - 3) = 0

Factor (x - 3) out of this,

(x - 3)(4x - 1) = 0

Therefore, x = {3, 1/4}

Answer 2

The quadratic formula is:

x = [- b ± √(b² - 4ac)] / 2a

Remember, "a" is the coefficient of the first term. "b" is the coefficient of the second term and "c" is the constant. Just plug those values into the formula directly from your equation and calculate the answer.

x = {- (-13) ± √[(-13)² - 4 (4)(3)]} / 2(4)

This particular equation is also factorable:

(4x - 1)(x - 3) = 0.

Set each factor equal to 0 and then solve.

Answer 3

The answer is (2xsquared+8x)(2xsquared-5x).