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A 4.86 kb ball traveling at 3.15 m/s collides with a 5.09 kg ball moving at 1.22 m/s in the same direction as the first ball. The collision is elastic.

a) Find the final velocity, magnitude + direction of each ball
b) Calculate how much energy was transfered during the collision and identify which ball gained and lost the energy.
c) Calculate the magnitude of the impulse that each ball experiences.

I think I got part a: I put 1.17 and 3.10.
I think part b is -9.57 and 9.62

But part b I didn't know how to do.

Thanks!

2007-03-29 14:16:13 · 1 answers · asked by truthiness89 2 in Science & Mathematics Physics

1 answers

Calculate the energy =1/2mv^2 for either ball before and after the collision, then subtract to find the change (transfer). The other will be the negative of the first.

2007-03-29 15:12:42 · answer #1 · answered by meg 7 · 0 0

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