An alloy that is one karat gold contains a weight of pure gold that is one part in twenty-four. What is the volume of gold in a 18.0 karat gold necklace whose weight is 1.24 N?
I have no idea even how to start this problem. I tried doing a % and i was WAY off...
2007-03-29 12:50:09 · 4 answers · asked by ..*Real-ality*.. 3 in Science & Mathematics ➔ Physics
Force = Mass * Acceleration, weight is the Force due to gravity where the mass is weighed.
1.24 N = m_necklace * g
g=9.8 m/s^2
m_necklace=12.9 grams
m_gold=m_necklace * (18karat/24karat)
m_gold=9.68 grams
Now that you have the mass of the gold, use the density of gold to get the volume
Density = Mass/Volume
Volume = Mass/Density
2007-03-29 12:54:40 · answer #1 · answered by snake_slinger 4 · 2⤊ 0⤋
Just change karat to percent. 18 karat is 18/24 gold, or 75% gold. That makes for .93N. If you have the density of gold you can change that to volume.
2007-03-29 13:22:53 · answer #2 · answered by Nomadd 7 · 0⤊ 0⤋
Pure gold is 24 carat so 18carats is 18/24 gold.
The volume of gold in this instance would be :
18/24 x 1.24N which is 0.93 N.
(whatever N is)
2007-03-29 12:56:56 · answer #3 · answered by Barry S 5 · 0⤊ 0⤋
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2016-12-15 11:36:01 · answer #4 · answered by kluesner 4 · 0⤊ 0⤋