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(2x^4+7x-2)/(X^2+3) thanks!

2007-03-29 09:23:51 · 3 answers · asked by politicinal 1 in Science & Mathematics Mathematics

3 answers

It looks like long division is the most likely way to get the answer.

Doing this I got this for the quotient: 2x^2 - 6 + (25x -2) /(x^2 +3) or 2x^2 - 6 remainder 25x - 2

2007-03-29 09:33:28 · answer #1 · answered by Ray 5 · 0 0

2x^4+7x-2/(x^2+3)= 2x^-6 + (7x+16)/(x^2+3)
use the long division scheme

2007-03-29 09:42:40 · answer #2 · answered by santmann2002 7 · 0 0

make sure you write 0x^3 and 0x^2 so it looks like x^2+3 / 2x^4 + 0x^3 + 0x^2 + 7x - 2

2007-03-29 09:40:08 · answer #3 · answered by Anonymous · 0 0

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