2007-03-29 09:10:09 · 8 answers · asked by MATT C 1 in Science & Mathematics ➔ Chemistry
It depends on what type of reaction it is. If it is a Disproportionation or dismutation reaction then it can act as both - an oxidation and a reduction agent. For example:
Cl2 (aq) + 2OH- (aq) ===> Cl- (aq) + ClO- (aq) + H2O (l)
In the following reaction, it is just an oxidising agent with value -1:
Cl2 (aq) + 2I- (aq) ===> 2Cl- (aq) + I2 (aq)
Hope this gives you an idea.
2007-03-30 10:19:30 · answer #1 · answered by Anonymous · 1⤊ 0⤋
the oxidation number of chlorine in the Cl- ion is -1
2007-03-29 16:15:58 · answer #2 · answered by Melinda 3 · 0⤊ 0⤋
oxidation # of Cl changes depending on the the compound it forms.
Cl has -1 in NaCl
Cl(s)= 0
2007-03-29 16:14:06 · answer #3 · answered by Phy A 5 · 0⤊ 0⤋
The oxidation number of chlorine is zero in its elemental form, i.e. Cl2(g).
2007-04-02 10:29:52 · answer #4 · answered by cccccrazy 2 · 0⤊ 0⤋
-1, 1, 3, 5, or 7, with -1 the most common.
2007-03-29 16:15:07 · answer #5 · answered by Anonymous · 3⤊ 0⤋
I seem to remember hearing that it varies from -2 to 7 depending on the compounds you are forming.
2007-03-30 09:25:47 · answer #6 · answered by unrealworld 1 · 0⤊ 1⤋
Generally '-1', but it can vary.
2007-03-29 17:18:06 · answer #7 · answered by lenpol7 7 · 0⤊ 0⤋
Cl
2007-03-29 16:15:31 · answer #8 · answered by daniel e 2 · 0⤊ 1⤋