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2 answers

t1/2 = .693/k
k = t1/2/.693

That's the formula, as for deriving it, well I don't know why you would want to do that.

2007-03-29 07:32:12 · answer #1 · answered by Roger 2 · 0 0

A = A0e^(-kt)

at half life A =A0/2 dividing two sites by A0

so 1/2 =e^(-kt)

2= e^kt

kt =ln2

t = ln2/k =0.693/k

2007-03-29 07:32:51 · answer #2 · answered by maussy 7 · 0 0

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