Christina Milian or Rihanna? I am on Christina's side! Did you guys here that Christina was supposed to sing 'SOS'. The only reason why Rihanna sung it because Christina refused. I hate Rihanna. She is just an ugly girl with a large forehead!! Christina was supid by refusing to sing that song!
2007-03-29 06:30:52 · 19 answers · asked by calipornication 5 in Entertainment & Music ➔ Polls & Surveys
Hmmm. News to me.
Of the two, I do prefer Christina.
2007-03-29 06:33:35 · answer #1 · answered by Abby 5 · 3⤊ 0⤋
Honestly I have no clue who these people are. But seeing as how you feel so strongly about 'ugly, big-headed' girls I will have to go with Christina. I vote for the underdog.
2007-03-29 06:35:28 · answer #2 · answered by untchble 5 · 2⤊ 0⤋
i don't really like either.. but i saw rihanna on my super sweet sixteen and she just seemed like a b*swear
2007-03-29 06:35:06 · answer #3 · answered by ThatGirl6 4 · 3⤊ 0⤋
I refuse to get involved, esp since I have no idea who they are.
2007-03-29 06:37:24 · answer #4 · answered by lucy02 6 · 0⤊ 1⤋
I will love who ever wins. Until then I have better things to do.
2007-03-29 06:34:26 · answer #5 · answered by NakasEvilTwin 6 · 1⤊ 1⤋
Time to get a life?
2007-03-29 06:36:00 · answer #6 · answered by diannegoodwin@sbcglobal.net 7 · 3⤊ 1⤋
In this case I am on MY side, sweetie you seem too interesting to waste energy on this insignificant crap.
Come now. . you can do better than this.
I KNOW you can.
:)
2007-03-29 06:36:19 · answer #7 · answered by Matticus Kole 4 · 3⤊ 1⤋
i think they should settle it with a dance off
that always works in the movies
2007-03-29 06:35:13 · answer #8 · answered by Huh? 4 · 5⤊ 0⤋
I don't know, I'm not really fussed, they both have unique voices and there own style.
2007-03-29 06:34:41 · answer #9 · answered by Pearl 5 · 2⤊ 1⤋
I sure am not on Sanjays side on american idol. also i hate socks. and did you know my birthday is tommarow. and i also think the asker avatar is hot.NO I AM NOT GAY!
2007-03-29 06:36:02 · answer #10 · answered by ~•PandaBearHug•~ 2 · 1⤊ 2⤋