1) (4x - 12) / (2x - 6)
Your first step is to factor top and bottom. Factor the greatest common factor for each one.
[ 4(x - 3) ] / [ 2(x - 3) ]
Now, note the common factor on the top and the bottom, of
(x - 3). Cancel. This leaves us with
4/2
Which we can again reduce, as just 2.
2) (21 - 3x) / (x^2 - 3x - 28)
First, factor top and bottom
[ 3(7 - x) ] / [ (x - 7)(x + 4) ]
Use the "negative one" technique to swap (7 - x) into (x - 7). This involves factoring out (-1). In other words,
b - a = (-1)(a - b), if we ever want to swap terms.
[ 3(-1)(x - 7) ] / [ (x - 7)(x + 4) ]
Cancel the common factor of (x - 7) on top and bottom.
[ 3(-1) ] / [ (x + 4) ]
Simplify.
-3/(x + 4)
2007-03-29 06:32:01
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answer #1
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answered by Puggy 7
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1. 4x-12/2x-6=
4(x-3)/2(x-3)
x-3 cancels out ,and 4 is divided by 2 to give 2 .
hence, the ans is 2
2. 21-3x/x^2-3x-28=
3(7-x)/x^2-7x+4x -28=
3(7-x)/x(x-7)+4(x-7)=
3(7-x)/(x+4)(x-7) = 3(7-x)/-(7+x)(x+4)= 3/-(x+4)
that is, 7-x cancels out.
answer = 3/-(x+4) or -3/(x+4)
2007-03-29 06:41:13
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answer #2
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answered by pinkyme 1
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4x-12 / 2x-6 =
2(2x-6) / 2x-6=
2
21-3x / x^2 -3x-28 =
3(7-x) / (x-7)(x+4) =
-3(x-7) / (x-7)(x+4) =
-3 / x+4
2007-03-29 06:40:09
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answer #3
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answered by TMemories 2
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for x^2-12x+35 discover 2 numbers which the multiply is 35 and sum is -12 so we've -7 & -5 for x^2-3x-28 ind 2 numbers which the multply is -28 and sum is -3 so we've 4 & -7 (x-7)(x-5) -------------- (x-7)(x+4) so (x-7) will cancel the shall we've (x-5) --------- (x-4)
2016-12-02 23:37:36
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answer #4
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answered by ? 4
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1. 4(x-3)
-----------
2(x-3)
x-3 cancel out and the 4 becomes a 2 and the 2 becomes a 1 answer= 2
2.-3(x-7)
-------------
(x+4)(x-7)
x-7 cancel out
answer = -3/x+4
2007-03-29 08:16:17
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answer #5
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answered by Dave aka Spider Monkey 7
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Hi
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thirteen years of teaching experience in math at college level, and currently I am working as a lecturer for an army engineering college author of math guide.
hi
i can within 10 minutes for $2
2007-04-02 06:03:15
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answer #6
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answered by valivety v 3
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1)4x-12/2x-6
4(x-3)/2(x-3)
2
2)21-3x/x^2-3x-28
-3x+21/x^2-3x-28
-3(x-7)/(x-7)(x+4)
-3/(x+4)
I hope this helps!
2007-03-29 06:39:51
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answer #7
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answered by Anonymous
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why do you want to read it ?
is it your Challenge or someting else tell me about it
2007-03-29 06:36:19
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answer #8
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answered by brave_skyper 1
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