How do I solve this problem using the square root property?
(2-3x)square=21
2007-03-29 05:38:44 · 5 answers · asked by Meowmix 2 in Science & Mathematics ➔ Mathematics
take square root of both sides
2-3x = +/- sqrt(21)
or 2+/-sqrt(21) = 3x (it is -/+ but does not mater)
or x = (2+sqrt(21))/3 or (2-sqrt(21))/3
2007-03-29 05:44:07 · answer #1 · answered by Mein Hoon Na 7 · 0⤊ 0⤋
(2 - 3x)^2 = 21
=> 2 - 3x = sqrt(21) or -sqrt(21)
=> 3x = 2 + sqrt(21) or 2 - sqrt(21)
=> x = (2 + sqrt(21)) / 3, or x = (2 - sqrt(21)) / 3
2007-03-29 05:45:12 · answer #2 · answered by biglildan 6 · 0⤊ 0⤋
2-3x = sqrt 21
-3x = (+/- sqrt 21) - 2
x = [(+/- sqrt 21) + 2 ] / 3
2007-03-29 05:45:09 · answer #3 · answered by piri82 3 · 0⤊ 0⤋
2-3x=21^2 so -x=(441-2)/3 then x= -439/3
2007-03-29 05:44:06 · answer #4 · answered by MadScientist 2 · 0⤊ 0⤋
(2-3x)^2 = 21
2-3x = (+/-) sqrt(21)
-3x = (+/-) sqrt(21) - 2
3x = 2 (+/-) sqrt(21)
x = (2 (+/-) sqrt(21))/3
2007-03-29 05:44:14 · answer #5 · answered by Bramblyspam 7 · 0⤊ 0⤋