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Find lim f(x) as x approaches negative 0 if:

f(x) = {x – 1 if x is less-than-or-equal-to -1
x^2 if -1 is less-than-or-equal-to x which is less-than-or- equal-to 0
(x + 2)^2 if x > 0}

2007-03-29 05:33:53 · 3 answers · asked by Anonymous in Science & Mathematics Mathematics

3 answers

If you're approaching 0 from the negative side, then you use the equation f(x) = x^2 and don't need to worry about the other two equations.
Plug zero into that, and you get f(0) = 0. That's your answer.

2007-03-29 05:40:24 · answer #1 · answered by Bramblyspam 7 · 0 0

the limit appraoces 0 as x goes to -0, using x^2 for -1>x <=0

2007-03-29 12:51:06 · answer #2 · answered by Anonymous · 0 0

the relevant piece of the function is:
x^2 for x <= 0

...since you are approaching 0 from the negative direction.
So lim f(x) = 0

2007-03-29 12:39:14 · answer #3 · answered by tedfischer17 3 · 0 0

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