Factor completely: 8x^2+6x-5?

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Factor completely: 8x^2+6x-5?

2007-03-29 04:54:49 · 3 answers · asked by carolsilveyderrick1956 1 in Science & Mathematics ➔ Mathematics

3 answers

There's no common factor, so jump right to factoring into two binomials:

(4x +5 )(2x -1)

2007-03-29 04:59:10 · answer #1 · answered by Kathleen K 7 · 0⤊ 0⤋

(2*x - 1) * (4*x + 5) is the complete factorization
upon expansion, this leads to
2*x*4*x +10*x - 4*x - 5
rearranging and combining like terms leads to the original
8*x^2 + 6*x - 5

2007-03-29 12:01:04 · answer #2 · answered by Tim J 1 · 0⤊ 0⤋

(4x+5)(2x-1)

2007-03-29 11:58:16 · answer #3 · answered by gebobs 6 · 0⤊ 0⤋