58x +87 =798
x=
2007-03-29 04:50:30 · 8 answers · asked by Pink 1 in Science & Mathematics ➔ Mathematics
58x + 87 = 798
58x = 711
x = 711/58
x = 12.3 (3 significant figures)
2007-03-29 04:54:39 · answer #1 · answered by Anonymous · 1⤊ 1⤋
to solve:
58x + 87 - 87 = 798 - 87
58x = 711
58x/58 = 711/58
x = 711/58, which is approximately 12.258620689655172413793103448276
2007-03-29 11:57:32 · answer #2 · answered by Tim J 1 · 0⤊ 0⤋
I get 12 with a remainder of 15. If you subtract 87 from both sides you get 58x=711. Then divide both sides by 58 to get the x by itself and 711 divided by 58 is 12. There is a remainer of 15. I think that's right, I'm stretching back to my algebraic roots.
2007-03-29 11:57:04 · answer #3 · answered by fmxkrazyone 6 · 0⤊ 0⤋
58x = 798-87
58x = 711
x = 711/58 = 12.26
2007-03-29 11:54:45 · answer #4 · answered by Ohioguy95 6 · 1⤊ 0⤋
lordofdr is right. Any precision beyond three sig figs is meaningless.
2007-03-29 12:01:38 · answer #5 · answered by gebobs 6 · 0⤊ 0⤋
12.26
2007-03-29 11:54:46 · answer #6 · answered by Aileen R 1 · 1⤊ 0⤋
12.26
2007-03-29 11:54:38 · answer #7 · answered by Jon 5 · 1⤊ 0⤋
12.258620689655172413793103448276
2007-03-29 11:56:06 · answer #8 · answered by neutron 3 · 0⤊ 0⤋