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2000 decennial census found 8,049,313 persons living in North Carolina. In 2005, Census Bureau estimated NC's population to be 8,683,242.

2007-03-29 04:35:31 · 5 answers · asked by Michele N 1 in Science & Mathematics Mathematics

5 answers

Take your change in population and divide that by your initial population

(8,683,242 - 8,049,313) / 8,049,313
633,929 / 8,049,313
= 0.07876
Multiply the decimal by 100% to convert to a percentage
0.07876 X 100% = 7.876%

2007-03-29 04:42:47 · answer #1 · answered by Ohioguy95 6 · 0 0

You measure any percent change, increase or decrease, by calculating the change in the value divided by the initial value, or value you started with. In this case, the change will be the difference in population between 2005 and 2000 and the initial value will be the 2000 census.

Change in population/starting population

(8,683,242-8,049,313)/8,049,313
633,929/8,049,313
=0.078755665

If you round this value and convert it to a percent, the change will be about 8%.

2007-03-29 04:42:50 · answer #2 · answered by Bhajun Singh 4 · 0 0

Population in 2005 - 8683242

Population in 2000 - 8049313

Increase - 633929

Increase over 2000 figure = 633929 / 8049313

As pecentage, we multiply by 100 = 7.875 approx

Pleae note that in all such problems we should take the first figure (in this case population in 2000 as the base) and compute the increase or decrease.

2007-03-29 04:53:16 · answer #3 · answered by Swamy 7 · 0 0

The absolute increase is found by taking the difference and dividing by 8,049,313 or 7.87%

The annual increase is 1.527% and is found by taking the log of the quotent, dividing by 5, and using that as an exponent in 10^x

2007-03-29 04:56:01 · answer #4 · answered by davidosterberg1 6 · 0 0

(8,683,242 - 8,049,313 ) / 8,049,313 = 0.079 * 100 = 7.9%

2007-03-29 04:39:15 · answer #5 · answered by MamaMia © 7 · 0 0

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